Understanding glm::lookAt()

Question

I am following a tutorial to learn OpenGL in which they used glm::lookAt() function to build a view but I cannot understand the working of glm::lookAt() and apparently, there is no detailed documentation of GLM. Can anyone help me understand the parameters and working of glm::lookAt() please?

GLM documentation says:

detail::tmat4x4<T> glm::gtc::matrix_transform::lookAt   
(   
    detail::tvec3< T > const &  eye,
    detail::tvec3< T > const &  center,
    detail::tvec3< T > const &  up 
)

My current understanding is that camera is located at eye and is faced towards center. (And I don't know what the up is)

Answer 1

The up vector is basically a vector defining your world's "upwards" direction. In almost all normal cases, this will be the vector (0, 1, 0) i.e. towards positive Y. eye is the position of the camera's viewpoint, and center is where you are looking at (a position). If you want to use a direction vector D instead of a center position, you can simply use eye + D as the center position, where D can be a unit vector for example.

As for the inner workings, or more details, this is a common basic function for building a view matrix. Try reading the docs for gluLookAt() which is functionally equivalent.

Answer 2

Here, the Up vector defines the "upwards" direction in your 3D world (for this camera). For example, the value of vec3(0, 0, 1) means the Z-axis points upwards.

Eye is the point where you virtual 3D camera is located.

And Center is the point which the camera looks at (center of the scene).

The best way to understand something is to make it yourself. Here is how a camera transformation can be constructed using 3 vectors: Eye, Center, and Up.

LMatrix4 LookAt( const LVector3& Eye, const LVector3& Center, const LVector3& Up )
{
    LMatrix4 Matrix;

    LVector3 X, Y, Z;

Create a new coordinate system:

    Z = Eye - Center;
    Z.Normalize();
    Y = Up;
    X = Y.Cross( Z );

Recompute Y = Z cross X:

    Y = Z.Cross( X );

The length of the cross product is equal to the area of the parallelogram, which is < 1.0 for non-perpendicular unit-length vectors; so normalize X, Y here:

    X.Normalize();
    Y.Normalize();

Put everything into the resulting 4x4 matrix:

    Matrix[0][0] = X.x;
    Matrix[1][0] = X.y;
    Matrix[2][0] = X.z;
    Matrix[3][0] = -X.Dot( Eye );
    Matrix[0][1] = Y.x;
    Matrix[1][1] = Y.y;
    Matrix[2][1] = Y.z;
    Matrix[3][1] = -Y.Dot( Eye );
    Matrix[0][2] = Z.x;
    Matrix[1][2] = Z.y;
    Matrix[2][2] = Z.z;
    Matrix[3][2] = -Z.Dot( Eye );
    Matrix[0][3] = 0;
    Matrix[1][3] = 0;
    Matrix[2][3] = 0;
    Matrix[3][3] = 1.0f;

    return Matrix;
}

Answer 3

detail::tmat4x4<T> glm::gtc::matrix_transform::lookAt   
(   
    detail::tvec3< T > const &  //eye position in worldspace
    detail::tvec3< T > const &  //the point where we look at
    detail::tvec3< T > const &  //the vector of upwords(your head is up)
)

It's not difficult, maybe you need to review the three coordinates: Object(or Model) coordinates, World coordinates and Camera(or View) coordinates.