jquery $.each() for objects

问题

<script>
    $(document).ready(function() {
        var data = { "programs": [ { "name":"zonealarm", "price":"500" }, { "name":"kaspersky", "price":"200" } ] };
        $.each(data.programs[0], function(key,val) {
            alert(key+val);
        });
    });
</script>

This code retrieves the first data. name:zonealarm and price:500. How can I retrieve all the data in the object? I tried $.each(data.programs, function(key,val) but it didn't worked. Should I put it in a loop?

回答1:

$.each() works for objects and arrays both:

var data = { "programs": [ { "name":"zonealarm", "price":"500" }, { "name":"kaspersky", "price":"200" } ] };

$.each(data.programs, function (i) {
    $.each(data.programs[i], function (key, val) {
        alert(key + val);
    });
});

...and since you will get the current array element as second argument:

$.each(data.programs, function (i, currProgram) {
    $.each(currProgram, function (key, val) {
        alert(key + val);
    });
});

回答2:

You are indeed passing the first data item to the each function.

Pass data.programs to the each function instead. Change the code to as below:

<script>     
    $(document).ready(function() {         
        var data = { "programs": [ { "name":"zonealarm", "price":"500" }, { "name":"kaspersky", "price":"200" } ] };         
        $.each(data.programs, function(key,val) {             
            alert(key+val);         
        });     
    }); 
</script> 

回答3:

Basically you need to do two loops here. The one you are doing already is iterating each element in the 0th array element.

You have programs: [ {...}, {...} ] so programs[0] is { "name":"zonealarm", "price":"500" } So your loop is just going over that.

You could do an outer loop over the array

$.each(data.programs, function(index) {

    // then loop over the object elements
    $.each(data.programs[index], function(key, value) {
        console.log(key + ": " + value);
    }

}

来源：https://stackoverflow.com/questions/6208052/jquery-each-for-objects