Python: raw_input and unsupported operand type(s)

不打扰是莪最后的温柔 提交于 2019-11-28 14:44:05
sam

raw_input always returns a str object. You need to explicitly convert the input to an int. You can either do

val = int(raw_input(...))

or

val = raw_input(...)
val = int(val) 

As others have mentioned, there are many errors in your code. Here is one:

if height == exit:

Same problem with weight condition. I am just going to point out as you didn't ask about this in question so I will let you find out what the problem is :).

Please use it this way

def calculator():

    weight = int(raw_input('Please enter your weight (kg):'))

    if weight >0 and weight > 0:
        height = int(raw_input('Please enter your height (m):')) 

        if height >0 and height > 0:
            bmi = (weight) / (height ** 2) 

            print "Your BMI is", bmi

            if bmi < 18.5:
                print 'You are underweight.'
            if bmi >= 18.5 and bmi < 25:
                print 'Your BMI is normal.'
            if bmi >= 25 and bmi < 30:
                print 'You are overweight.'
            if bmi >= 30:
                print 'You are obese.'      

        else:   
            height = int(raw_input('Please state a valid number (m):'))
        if height == exit:
            exit()

    else:
        weight = int(raw_input('Please state a valid number (kg):'))

    if weight == exit:
        exit()

You need to cast input entries to int because they are strings.

And you no longer have to check if it is a digit,

Still, I suggest you add another condition like:

if weight and height:
    #Do stuff

In case no entry was provided.

EDIT:

/!\ In case you need decimals cast them to float

the numbers entered should be converted to float. just change the bmi = float(weight)/(float(height)** 2) You are good to go

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