Custom deserialization

自闭症网瘾萝莉.ら 提交于 2019-11-28 12:43:32

You need to create an IBsonSerializer or SerializerBase<> and attach it to the property you wish to serialize using the BsonSerializerAttribute. Something like the following:

public class BsonStringNumericSerializer : SerializerBase<double>
{
    public override double Deserialize(BsonDeserializationContext context, BsonDeserializationArgs args)
    {
        var type = context.Reader.GetCurrentBsonType();
        if (type == BsonType.String)
        {
            var s = context.Reader.ReadString();
            if (s.Equals("N/A", StringComparison.InvariantCultureIgnoreCase))
            {
                return 0.0;
            }
            else
            {
                return double.Parse(s);
            }
        }
        else if (type == BsonType.Double)
        {
            return context.Reader.ReadDouble();
        }
        // Add any other types you need to handle
        else
        {
            return 0.0;
        }
    }
}

public class YourClass
{
    [BsonSerializer(typeof(BsonStringNumericSerializer))]
    public double YourDouble { get; set; }
}

If you don't want to use attributes you can create an IBsonSerializationProvider and register it using BsonSerializer.RegisterSerializationProvider.

Full documentation of MongoDB C# Bson serialization can be found here

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