Better way to convert list to vector?

问题

I have a list of named values:

myList <- list(\'A\'=1, \'B\'=2, \'C\'=3)

I want a vector with the value 1:3

I can\'t figure out how to extract the values without defining a function. Is there a simpler way that I\'m unaware of?

library(plyr)
myvector <- laply(myList, function(x) x)

Is there something akin to myList$Values to strip the names and return it as a vector?

回答1:

Use unlist with use.names = FALSE argument.

unlist(myList, use.names=FALSE)

回答2:

purrr::flatten_*() is also a good option. the flatten_* functions add thin sanity checks and ensure type safety.

myList <- list('A'=1, 'B'=2, 'C'=3)

purrr::flatten_dbl(myList)
## [1] 1 2 3

回答3:

This can be done by using unlist before as.vector. The result is the same as using the parameter use.names=FALSE.

as.vector(unlist(myList))

来源：https://stackoverflow.com/questions/17094774/better-way-to-convert-list-to-vector