问题
How to generate an n-gram of a string like:
String Input=\"This is my car.\"
I want to generate n-gram with this input:
Input Ngram size = 3
Output should be:
This
is
my
car
This is
is my
my car
This is my
is my car
Give some idea in Java, how to implement that or if any library is available for it.
I am trying to use this NGramTokenizer but its giving n-gram\'s of character sequence and I want n-grams of word sequence.
回答1:
You are looking for ShingleFilter.
Update: The link points to version 3.0.2. This class may be in different package in newer version of Lucene.
回答2:
I believe this would do what you want:
import java.util.*;
public class Test {
public static List<String> ngrams(int n, String str) {
List<String> ngrams = new ArrayList<String>();
String[] words = str.split(" ");
for (int i = 0; i < words.length - n + 1; i++)
ngrams.add(concat(words, i, i+n));
return ngrams;
}
public static String concat(String[] words, int start, int end) {
StringBuilder sb = new StringBuilder();
for (int i = start; i < end; i++)
sb.append((i > start ? " " : "") + words[i]);
return sb.toString();
}
public static void main(String[] args) {
for (int n = 1; n <= 3; n++) {
for (String ngram : ngrams(n, "This is my car."))
System.out.println(ngram);
System.out.println();
}
}
}
Output:
This
is
my
car.
This is
is my
my car.
This is my
is my car.
An "on-demand" solution implemented as an Iterator:
class NgramIterator implements Iterator<String> {
String[] words;
int pos = 0, n;
public NgramIterator(int n, String str) {
this.n = n;
words = str.split(" ");
}
public boolean hasNext() {
return pos < words.length - n + 1;
}
public String next() {
StringBuilder sb = new StringBuilder();
for (int i = pos; i < pos + n; i++)
sb.append((i > pos ? " " : "") + words[i]);
pos++;
return sb.toString();
}
public void remove() {
throw new UnsupportedOperationException();
}
}
回答3:
This code returns an array of all Strings of the given length:
public static String[] ngrams(String s, int len) {
String[] parts = s.split(" ");
String[] result = new String[parts.length - len + 1];
for(int i = 0; i < parts.length - len + 1; i++) {
StringBuilder sb = new StringBuilder();
for(int k = 0; k < len; k++) {
if(k > 0) sb.append(' ');
sb.append(parts[i+k]);
}
result[i] = sb.toString();
}
return result;
}
E.g.
System.out.println(Arrays.toString(ngrams("This is my car", 2)));
//--> [This is, is my, my car]
System.out.println(Arrays.toString(ngrams("This is my car", 3)));
//--> [This is my, is my car]
回答4:
/**
*
* @param sentence should has at least one string
* @param maxGramSize should be 1 at least
* @return set of continuous word n-grams up to maxGramSize from the sentence
*/
public static List<String> generateNgramsUpto(String str, int maxGramSize) {
List<String> sentence = Arrays.asList(str.split("[\\W+]"));
List<String> ngrams = new ArrayList<String>();
int ngramSize = 0;
StringBuilder sb = null;
//sentence becomes ngrams
for (ListIterator<String> it = sentence.listIterator(); it.hasNext();) {
String word = (String) it.next();
//1- add the word itself
sb = new StringBuilder(word);
ngrams.add(word);
ngramSize=1;
it.previous();
//2- insert prevs of the word and add those too
while(it.hasPrevious() && ngramSize<maxGramSize){
sb.insert(0,' ');
sb.insert(0,it.previous());
ngrams.add(sb.toString());
ngramSize++;
}
//go back to initial position
while(ngramSize>0){
ngramSize--;
it.next();
}
}
return ngrams;
}
Call:
long startTime = System.currentTimeMillis();
ngrams = ToolSet.generateNgramsUpto("This is my car.", 3);
long stopTime = System.currentTimeMillis();
System.out.println("My time = "+(stopTime-startTime)+" ms with ngramsize = "+ngrams.size());
System.out.println(ngrams.toString());
Output:
My time = 1 ms with ngramsize = 9 [This, is, This is, my, is my, This is my, car, my car, is my car]
回答5:
public static void CreateNgram(ArrayList<String> list, int cutoff) {
try
{
NGramModel ngramModel = new NGramModel();
POSModel model = new POSModelLoader().load(new File("en-pos-maxent.bin"));
PerformanceMonitor perfMon = new PerformanceMonitor(System.err, "sent");
POSTaggerME tagger = new POSTaggerME(model);
perfMon.start();
for(int i = 0; i<list.size(); i++)
{
String inputString = list.get(i);
ObjectStream<String> lineStream = new PlainTextByLineStream(new StringReader(inputString));
String line;
while ((line = lineStream.read()) != null)
{
String whitespaceTokenizerLine[] = WhitespaceTokenizer.INSTANCE.tokenize(line);
String[] tags = tagger.tag(whitespaceTokenizerLine);
POSSample sample = new POSSample(whitespaceTokenizerLine, tags);
perfMon.incrementCounter();
String words[] = sample.getSentence();
if(words.length > 0)
{
for(int k = 2; k< 4; k++)
{
ngramModel.add(new StringList(words), k, k);
}
}
}
}
ngramModel.cutoff(cutoff, Integer.MAX_VALUE);
Iterator<StringList> it = ngramModel.iterator();
while(it.hasNext())
{
StringList strList = it.next();
System.out.println(strList.toString());
}
perfMon.stopAndPrintFinalResult();
}catch(Exception e)
{
System.out.println(e.toString());
}
}
Here is my codes to create n-gram. In this case, n = 2, 3. n-gram of words sequence which smaller than cutoff value will ignore from result set. Input is list of sentences, then it parse using a tool of OpenNLP
回答6:
public static void main(String[] args) {
String[] words = "This is my car.".split(" ");
for (int n = 0; n < 3; n++) {
List<String> list = ngrams(n, words);
for (String ngram : list) {
System.out.println(ngram);
}
System.out.println();
}
}
public static List<String> ngrams(int stepSize, String[] words) {
List<String> ngrams = new ArrayList<String>();
for (int i = 0; i < words.length-stepSize; i++) {
String initialWord = "";
int internalCount = i;
int internalStepSize = i + stepSize;
while (internalCount <= internalStepSize
&& internalCount < words.length) {
initialWord = initialWord+" " + words[internalCount];
++internalCount;
}
ngrams.add(initialWord);
}
return ngrams;
}
回答7:
Check this out:
public static void main(String[] args) {
NGram nGram = new NGram();
String[] tokens = "this is my car".split(" ");
int i = tokens.length;
List<String> ngrams = new ArrayList<>();
while (i >= 1){
ngrams.addAll(nGram.getNGram(tokens, i, new ArrayList<>()));
i--;
}
System.out.println(ngrams);
}
private List<String> getNGram(String[] tokens, int n, List<String> ngrams) {
StringBuilder strbldr = new StringBuilder();
if (tokens.length < n) {
return ngrams;
}else {
for (int i=0; i<n; i++){
strbldr.append(tokens[i]).append(" ");
}
ngrams.add(strbldr.toString().trim());
String[] newTokens = Arrays.copyOfRange(tokens, 1, tokens.length);
return getNGram(newTokens, n, ngrams);
}
}
Simple recursive function, better running time.
来源：https://stackoverflow.com/questions/3656762/n-gram-generation-from-a-sentence