An array of length N can contain values 1,2,3 … N^2. Is it possible to sort in O(n) time?

旧城冷巷雨未停 提交于 2019-11-28 09:27:30

Write each integer in base N, that is each x can be represented as (x1, x2) with x = 1 + x1 + x2*N. Now you can sort it twice with counting sort, once on x1 and once on x2, resulting in the sorted array.

Yes, you can, using radix sort with N buckets and two passes. Basically, you treat the numbers as having 2 digits in base N.

It is possible to sort any array of integers with a well defined maximum value in O(n) time using a radix sort. This is likely the case for any list of integers you encounter. For example if you were sorting a list of arbitrary precision integers it wouldn't be true. But all the C integral types have well-defined fixed ranges.

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