Subtracting two annotated columns

问题

I need to be able to sort on the aggregate of two annotated columns

So I'd like to do something like this:

c = c.annotate(metric=Sum('results__metric'))
c = c.annotate(metric_prior=Sum('results__metric_prior'))
c = c.annotate(variance=F('metric')-F('metric_prior')) #doesn't work, for demonstrative purposes only

and then:

c = c.order_by('variance')

Does anyone know how to accomplish something like the above?

回答1:

Actually,

c = c.annotate(variance=F('metric')-F('metric_prior'))

works as you would like it to starting with Django 1.8.

Moreover, you can also order by an expression, which means you can just use:

c = c.order_by(F('metric') - F('metric_prior'))

or even just:

c = c.order_by(Sum('results__metric') - Sum('results__metric_prior'))

回答2:

Ticket is there for more than 4 years (by 2014), but it can be accomplished with a little .extra() query, like this:

items = MyModel.objects.extra(
    select = {'variance': 'SUM(relatedModel__someField) - SUM(relatedModel__someField)'},
)

Yes, it can be a bit unpredictable with different DBMS. But if you limit the syntax inside extra to very common SQL it should work more or less everywhere.

来源：https://stackoverflow.com/questions/17374467/subtracting-two-annotated-columns