Lets say I have these columns
uniqueID|Money|Quantity|MoneyOrder|QuantityOrder
1|23|12||
2|11|9||
3|99|100||
What I want to do is update MoneyOrder
and QuantityOrder
based on the value of ORDER BY
.
So the results would be:
uniqueID|Money|Quantity|MoneyOrder|QuantityOrder
1|23|12|2|1
2|11|90|1|2
3|99|100|3|3
I want the update to operate like an identity column without actually making it an identity column. I know that I could just order by 'x' and the order would be the result but I want to generate a report where you can see the item line by line.
Is something like this possible update mytable set Moneyorder = 'imnotsure' order by MoneyOrder asc
?
SET @rownumber = 0;
update mytable set Moneyorder = (@rownumber:=@rownumber+1)
order by MoneyOrder asc
or to do it in a single query you can try
update mytable target
join
(
select id, (@rownumber := @rownumber + 1) as rownum
from mytable
cross join (select @rownumber := 0) r
order by MoneyOrder asc
) source on target.id = source.id
set Moneyorder = rownum
Salman A
See answers to this question:
Updating column so that it contains the row position
SET @counter = 0;
UPDATE
my_table
SET MoneyOrder = @counter := @counter + 1
ORDER BY Money;
SET @counter = 0;
UPDATE
my_table
SET QuantityOrder = @counter := @counter + 1
ORDER BY Quantity;
来源:https://stackoverflow.com/questions/10485769/mysql-update-a-column-with-an-int-based-on-order