Regular expressions in findstr

风格不统一 提交于 2019-11-28 06:16:41

This works for me:

findstr /r "^[1-9][0-9]*$ ^-[1-9][0-9]*$ ^0$"

If you don't use the /c option, the <Strings> argument is treated as a space-separated list of search strings, which makes the space a sort of crude replacement for the | construct. (As long as your regexes don't contain spaces, that is.)

Argh, I should have read the documentation better. findstr apparently doesn't support alternations (|).

So I'm probably back to multiple invocations or replacing the whole thing with a custom parser eventually.

This is what I do for now:

set ERROR=1
rem Test for zero
echo %1|findstr /r /c:"^0$">nul 2>&1
if not errorlevel 1 set ERROR=
rem Test for positive numbers
echo %1|findstr /r /c:"^[1-9][0-9]*$">nul 2>&1
if not errorlevel 1 set ERROR=
rem Test for negative numbers
echo %1|findstr /r /c:"^-[1-9][0-9]*$">nul 2>&1
if not errorlevel 1 set ERROR=

Or if you can, download grep for windows.. Many more features than findstr provides.

martski

A simpler regex that achieves the same thing is possible, just add an optional minus to the start of your original expression:

^-?[0-9][0-9]*$

Support for regex in findstr is quite limited. I suggest using Notepad++. The find in files option supports Perl Compatible Regular Expressions; results showing filename, line number and matching text can be easily copied to a text file.

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