MYSQL how to select data where a field has a min value

╄→гoц情女王★ 提交于 2019-11-28 05:49:36

this will give you result that has the minimum price on all records.

SELECT *
FROM pieces
WHERE price =  ( SELECT MIN(price) FROM pieces )

This is how I would do it (assuming I understand the question)

SELECT * FROM pieces ORDER BY price ASC LIMIT 1

If you are trying to select multiple rows where each of them may have the same price (which is the minimum) then @JohnWoo's answer should suffice.

Basically here we are just ordering the results by the price in ASCending order (increasing) and taking the first row of the result.

Use HAVING MIN(...)

Something like:

SELECT MIN(price) AS price, pricegroup
FROM articles_prices
WHERE articleID=10
GROUP BY pricegroup
HAVING MIN(price) > 0;

In fact, depends what you want to get: - Just the min value:

SELECT MIN(price) FROM pieces
  • A table (multiples rows) whith the min value: Is as John Woo said above.

  • But, if can be different rows with same min value, the best is ORDER them from another column, because after or later you will need to do it (starting from John Woo answere):

    SELECT * FROM pieces WHERE price = ( SELECT MIN(price) FROM pieces) ORDER BY stock ASC

This also works:

SELECT
  pieces.*
FROM
  pieces inner join (select min(price) as minprice from pieces) mn
  on pieces.price = mn.minprice

(since this version doesn't have a where condition with a subquery, it could be used if you need to UPDATE the table, but if you just need to SELECT i would reccommend to use John Woo solution)

Vijay Maurya

Efficient way (with any number of records):

SELECT id, name, MIN(price) FROM (select * from table order by price) as t group by id

To make it simpler

SELECT *,MIN(price) FROM prod LIMIT 1

  • Put * so it will display the all record of the minimum value
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