How do you use the non-default constructor for a member?

问题

I have two classes

class a {
    public:
        a(int i);
};

class b {
    public:
        b(); //Gives me an error here, because it tries to find constructor a::a()
        a aInstance;
}

How can I get it so that aInstance is instantiated with a(int i) instead of trying to search for a default constructor? Basically, I want to control the calling of a\'s constructor from within b\'s constructor.

回答1:

You need to call a(int) explicitly in the constructor initializer list:

b() : aInstance(3) {}

Where 3 is the initial value you'd like to use. Though it could be any int. See comments for important notes on order and other caveats.

回答2:

Use an initialization list:

b::b() : aInstance(1) {}

回答3:

Just use a constructor which is defined like this:

class b {
public:
    b()
    : aInstance(5)
    {}
    a aInstance;
};

回答4:

The top two answers won't work. You put class declarations in the .h header files, and (member) function definitions in the .cpp files. The braces {} that the respondents have put define the b constructor block. In practice no one would want that empty. Yet you can't define it properly in the .cpp or the compiler will report error of 'redefinition'. (As the linker would anyway if the header file is #included in several translation units) Since the purpose of header files is that they CAN be included in several .cpp's the answers above are unfeasable.

回答5:

I think you should use a pointer to 'a' like:

class b {
public:
    b() : aInstance(new a(5)) {}
    a *aInstance;
};

This way you will have defined behaviour. Of course you will need to free *aInstance in the destructor.

来源：https://stackoverflow.com/questions/2088944/how-do-you-use-the-non-default-constructor-for-a-member

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c++

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constructor

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member