Get time since epoch in milliseconds, preferably using C++11 chrono

血红的双手。 提交于 2019-11-28 04:29:21
Mike Seymour
unsigned long milliseconds_since_epoch =
    std::chrono::system_clock::now().time_since_epoch() / 
    std::chrono::milliseconds(1);

although, especially since you want platform independence, it might be better to replace unsigned long with a type that's more likely to be large enough:

  • (unsigned) long long
  • std::(u)int64_t
  • std::chrono::milliseconds::rep
  • auto

To me, this clearly states both that you're risking loss of precision (by analogy with integer division) and that you're leaving the safety of the type system (by dividing by a typed time to give a unitless number). However, as demonstrated in the comments, some people would say that any attempt to move away from type-safety should be accompanied by a deliberate attempt to make the code look dangerous. If you need to deal with people who hold that belief, it might be simpler to use duration_cast rather than enter into an argument about irrelevant stylistic choices:

unsigned long milliseconds_since_epoch = 
    std::chrono::duration_cast<std::chrono::milliseconds>
        (std::chrono::system_clock::now().time_since_epoch()).count();
标签
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!