Order a List (C#) by many fields? [duplicate]

北慕城南 提交于 2019-11-28 04:26:42

Use ThenBy:

Customer.OrderBy(c => c.LastName).ThenBy(c => c.FirstName)

See MSDN: http://msdn.microsoft.com/en-us/library/bb549422.aspx

Yes, you can do it by specifying the comparison method. The advantage is the sorted object don't have to be IComparable

   aListOfObjects.Sort((x, y) =>
   {
       int result = x.A.CompareTo(y.A);
       return result != 0 ? result : x.B.CompareTo(y.B);
   });

Make your object something like

public class MyObject : IComparable
{
    public string a;
    public string b;

    virtual public int CompareTo(object obj)
    {
        if (obj is MyObject)
        {
            var compareObj = (MyObject)obj;
            if (this.a.CompareTo(compareObj.a) == 0)
            {
                // compare second value
                return this.b.CompareTo(compareObj.b);
            }
            return this.a.CompareTo(compareObj.b);
        }
        else
        {
            throw new ArgumentException("Object is not a MyObject ");
        }
    }
}

also note that the returns for CompareTo :

http://msdn.microsoft.com/en-us/library/system.icomparable.compareto.aspx

Then, if you have a List of MyObject, call .Sort() ie

var objList = new List<MyObject>();
objList.Sort();

Your object should implement the IComparable interface.

With it your class becomes a new function called CompareTo(T other). Within this function you can make any comparison between the current and the other object and return an integer value about if the first is greater, smaller or equal to the second one.

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