How to check if bootstrap modal is open, so i can use jquery validate

♀尐吖头ヾ 提交于 2019-11-28 04:14:42

To avoid the race condition @GregPettit mentions, one can use:

($("element").data('bs.modal') || {})._isShown    // Bootstrap 4
($("element").data('bs.modal') || {}).isShown     // Bootstrap <= 3

as discussed in Twitter Bootstrap Modal - IsShown.

When the modal is not yet opened, .data('bs.modal') returns undefined, hence the || {} - which will make isShown the (falsy) value undefined. If you're into strictness one could do ($("element").data('bs.modal') || {isShown: false}).isShown

You can use

$('#myModal').hasClass('in');

Bootstrap adds the in class when the modal is open and removes it when closed

alexoviedo999

You can also directly use jQuery.

$('#myModal').is(':visible');
$("element").data('bs.modal').isShown

won't work if the modal hasn't been shown before. You will need to add an extra condition:

$("element").data('bs.modal')

so the answer taking into account first appearance:

if ($("element").data('bs.modal') && $("element").data('bs.modal').isShown){
... 
}

Check if a modal is open

$('.modal:visible').length && $('body').hasClass('modal-open')

To attach an event listener

$(document).on('show.bs.modal', '.modal', function () {
    // run your validation... ( or shown.bs.modal )
});

Bootstrap 2,3,4 Check is any modal open in page :

if($('.modal.in').length)

On bootstrap-modal.js v2.2.0:

( $('element').data('modal') || {}).isShown
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