Open Link to Instagram Native

问题

To open a Facebook Native profile, I can use:

NSURL *url = [NSURL URLWithString:@"fb://profile/<id>"];
[[UIApplication sharedApplication] openURL:url];

Is there any way to do the same thing for an Instagram profile?

回答1:

Following Snippet will open instagram app on your device with userName.

Objective C

NSURL *instagramURL = [NSURL URLWithString:@"instagram://user?username=USERNAME"];
if ([[UIApplication sharedApplication] canOpenURL:instagramURL]) {
    [[UIApplication sharedApplication] openURL:instagramURL];
}

Swift

var instagramURL: NSURL = NSURL(string: "instagram://user?username=USERNAME")
if UIApplication.sharedApplication().canOpenURL(instagramURL) {
    UIApplication.sharedApplication().openURL(instagramURL)
}

Swift 3.0

let instagramURL:URL = URL(string: "instagram://user?username=USERNAME")!
if UIApplication.shared.canOpenURL(instagramURL) {
    UIApplication.shared.open(instagramURL, options:[:], completionHandler: { (Bool) in
        print("Completion block")
    })
}

if you want more details about it you can refere following Documentation link

来源：https://stackoverflow.com/questions/16369798/open-link-to-instagram-native