Pyqt how to get a widget's dimensions

问题

I am currently developing an application in which i cannot use modal windows (due to some application constraints). However, in some cases i would like to simulate a popup window. To do so i dynamically create a widget that has the centralwidget as parent and i use the move() method to place it where i want. I would like to know if there is a way to get a widget's dimensions at a given time (considering the mainWindow can be resized at any time) so that i will be able to center the placeholder popup (a simple widget) at the middle of the centralwidget.

Thank you

回答1:

You can use frameGeometry or geometry depending on your needs.

回答2:

For getting Qt Widget size:

import sys
from PyQt4 import QtGui, QtCore

app = QtGui.QApplication(sys.argv)

mainWindow = QtGui.QWidget()
width = mainWindow.frameGeometry().width()
height = mainWindow.frameGeometry().height()

回答3:

For gettting screen size

import sys
from PyQt4 import QtGui, QtCore

app = QtGui.QApplication(sys.argv)

mainWindow = QtGui.QWidget()
screenShape = QtGui.QDesktopWidget().screenGeometry()
mainWindow.resize(self.screenShape.width(), self.screenShape.height())
mainWindow.show()

来源：https://stackoverflow.com/questions/15204470/pyqt-how-to-get-a-widgets-dimensions