Splitting a list into two seperate lists, by every other item in python

问题

Hello I have a quick question I cant seem to solve.

I have a list:

a = [item1, item2, item3, item4, item5, item6]

And I want to split this list into two seperate ones by everything other item such that:

b = [item1, item3, item5]
c = [item2, item4, item6]

回答1:

Use slicing, specifying a step:

b,c = a[::2], a[1::2]

回答2:

Using filter is one option:

a = [item1, item2, item3, item4, item5, item6]
b = filter(lambda x: a.index(x) % 2 == 0, a)
c = filter(lambda x: a.index(x) % 2 != 0, a)

EDIT: This would require for the elements to be unique and is inefficient.

来源：https://stackoverflow.com/questions/22162074/splitting-a-list-into-two-seperate-lists-by-every-other-item-in-python