问题
I have 3 ajax call. Data from each ajax call is passed to john_doe();
Call 1
$.ajax({
url: url1,
dataType: "JSON",
type: "GET",
}).success(function(data1){
john_doe(data1);
});
Call 2
$.ajax({
url: url2,
dataType: "JSON",
type: "GET",
}).success(function(data2){
john_doe(data2);
});
Call 3
$.ajax({
url: url3,
dataType: "JSON",
type: "GET",
}).success(function(data3){
john_doe(data3);
});
Main function
function john_doe(param){
console.log(param); //Print data from all three ajax call.
}
How to separate data1, data2 and data3 in john_doe function? because I need to carry out arithmetic operation.
Currently,
Input
data1 = one,two,three
data2 = four
data3 = five
Output
console.log(param) would give output as
one
four
five
I want output as
console.log(param[0])
console.log(param[1])
console.log(param[2])
param[0] containing one,two,three
param[1] containing four
param[2] containing five
I dont have control over the data. How to access data1, data2 and data3 separately?
回答1:
Quick and dirty solution is simply pass in an identifier, why is this dirty because it isn't really extensible with respect to adding say 4th or 5th call each time you do this you need to add more identifiers and your if statement in the main method will end up pretty ugly at one point. But that said sometimes "Keeping It Simple" is ok.
Main function:
function john_doe(identifier, param) {
// best to use something more readable then numbers
if(identifier == 1) {
console.log(param); //Print data from all ajax call 1.
} else if(identifier == 2) {
console.log(param); //Print data from all ajax call 2.
} else if(identifier == 23) {
console.log(param); //Print data from all ajax call 3.
} else {
// handle bad id
}
}
In your ajax calls, pass in the right identifier, for example Call 2:
$.ajax({
url: url2,
dataType: "JSON",
type: "GET",
}).success(function(data2){
// numeric 2 in in the first param is your identifier
john_doe(2,data2); });
回答2:
Using promises you can access all the data in Promise.all() callback and do whatever you need with it all at once. Assumes using jQuery 3+. Can use $.when
in older versions
var urls =['data-1.json','data-2.json','data-3.json'];
// array of ajax promises
var reqPromises = urls.map(function(url){
return $.ajax({
url: url,
dataType: "JSON",
type: "GET"
});
});
Promise.all(reqPromises).then(function(res){
// res is array of all the objects sent to each `$.ajax` from server
// in same order that urls are in
var param = res.map(function(item){
return item.val
});
console.log(param)
})
DEMO
回答3:
Adding a param to let you know where it is being called from
Call 1
$.ajax({
url: url1,
dataType: "JSON",
type: "GET",
}).success(function(data){
john_doe('call1',data);
});
Call 2
$.ajax({
url: url2,
dataType: "JSON",
type: "GET",
}).success(function(data){
john_doe('call2',data);
});
Call 3
$.ajax({
url: url3,
dataType: "JSON",
type: "GET",
}).success(function(data){
john_doe('call3',data);
});
Main function
function john_doe(call,data){
console.log('Called from : ' + call);
console.log(data); //Print data from all three ajax call.
}
回答4:
How about this? Declare an object container to hold your response data values and your arithmetic operation function.
var myParams = {
all_params: [],
getParams: function(){
return this.all_params;
},
setParam: function(index, data){
this.all_params[index] = data;
},
yourArithmeticOperation: function(){
console.log(this.all_params); // your actual logic using all 3 ajax response data
}
}
Then, in your ajax calls:
// call 1
$.ajax({
url: url1,
dataType: "JSON",
type: "GET",
}).success(function(data){
myParams.setParam(0, data); // add ajax 1 response data
});
// call 2
$.ajax({
url: url1,
dataType: "JSON",
type: "GET",
}).success(function(data){
myParams.setParam(1, data); // add ajax 2 response data
});
// call 3
$.ajax({
url: url1,
dataType: "JSON",
type: "GET",
}).success(function(data){
myParams.setParam(2, data); // add ajax 3 response data
});
In case you need all your response data,
// after all three ajax calls
params = myParams.getParams();
console.log(params);
And finally, your arithmetic operation,
myParams.yourArithmeticOperation();
回答5:
try adding async: false
to your ajax calls
$.ajax({
url: url1,
dataType: "JSON",
type: "GET",
async: false,
}).success(function(data){
john_doe('call1',data);
});
来源:https://stackoverflow.com/questions/43309387/multiple-ajax-call-to-single-function-javascript