问题
As the title says, I am trying to dynamically load content in a view using ajax requests. I know this can be done if you are using html
elements e.g. ("#div_place").html(<p>...)
. The problem lies when I would like to load some php/blade objects into a div for instance. Is this possible or is there a different way to go about achieving the result I want.
回答1:
This is pretty straightforward. Assuming you're using jQuery...
create a route that will respond to the AJAX call and return an HTML fragment
Route::get('test', function(){ // this returns the contents of the rendered template to the client as a string return View::make("mytemplate") ->with("value", "something") ->render(); });
in your javascript:
$.get( "test", function (data) { $("#my-content-div").html(data); } );
回答2:
After some digging some more I found this which helped me to solve the problem.
You have to use the .load("url/page/...")
via jquery and then set a route in the routes.php file that displays a view with the data that needs to be loaded e.g.
Route::get('/url/page/...', function(){
return View::make('test');
});
This returns the necessary php code which needed to be loaded dynamically, cheers.
来源:https://stackoverflow.com/questions/24812785/how-to-load-blade-or-php-content-into-a-view-via-ajax-jquery-in-laravel