问题
First, I have to mention that I already look through many questions in stackoverflow, but many doesn't answer my question. Not to mention many doesn't even have an answer.
How do I achieve the following, making sure functionB()
executes after functionA()
finishes?
Note: I do not want to convert my async functions to new Promise(resolve=>{...})
because I'll have to convert the someServiceThatMakesHTTPCall()
as well, and any other async functions within the call stack, which is a big change.
function functionThatCannotHaveAsyncKeyword() {
functionA()
.then(async function() {
await functionB();
})
.then(function() {
console.log('last');
});
}
async function functionA() {
console.log('first');
await someServiceThatMakesHTTPCall();
}
async function functionB() {
console.log('second');
await someServiceThatMakesHTTPCall();
}
回答1:
Your approach using await
in an async
then
callback will work, but it's unnecessarily complex if all you want to do is call the async
function and have its result propagate through the chain. But if you are doing other things and want the syntax benefit of async
functions, that's fine. I'll come back to that in a moment.
async
functions returns promises, so you just return the result of calling your function:
function functionThatCannotHaveAsyncKeyword() {
functionA()
.then(function() {
return functionB(someArgument);
})
.then(function() {
console.log('last');
}); // <=== Note: You need a `catch` here, or this function needs
// to return the promise chain to its caller so its caller can
// handle errors
}
If you want to pass functionA
's resolution value into functionB
, you can do it even more directly:
functionA()
.then(functionB)
// ...
When you return a promise from a then
callback, the promise created by the call to then
is slaved to the promise you return.
Example:
const wait = (duration, ...args) => new Promise(resolve => {
setTimeout(resolve, duration, ...args);
});
async function functionA() {
await wait(500);
return 42;
}
async function functionB() {
await wait(200);
return "answer";
}
functionB()
.then(result => {
console.log(result); // "answer"
return functionA();
})
.then(result => {
console.log(result); // 42
})
.catch(error => {
// ...handle error...
});
Coming back to your approach using an async
then
callback: That works too, and makes sense when you're doing more stuff:
const wait = (duration, ...args) => new Promise(resolve => {
setTimeout(resolve, duration, ...args);
});
async function functionA() {
await wait(500);
return 42;
}
async function functionB() {
await wait(200);
return "answer";
}
functionB()
.then(async (result) => {
console.log(result); // "answer"
const v = await functionA();
if (v < 60) {
console.log("Waiting 400ms...");
await wait(400);
console.log("Done waiting");
}
console.log(v); // 42
})
.catch(error => {
// ...handle error...
});
回答2:
You can use promise inside the first method as
function functionThatCannotHaveAsyncKeyword() {
return new Promise(async(resolve, reject)=> {
await functionA();
await functionB();
console.log('last');
resolve();
});
}
async function functionA() {
console.log('first');
await someServiceThatMakesHTTPCall();
}
async function functionB() {
console.log('second');
await someServiceThatMakesHTTPCall();
}
回答3:
if someServiceThatMakesHTTPCall
is async you can avoid all that by doing the following:
function functionThatCannotHaveAsyncKeyword() {
functionA()
.then(function() {
return functionB()
})
.then(function() {
console.log('last');
});
}
function functionA() {
console.log('first');
return someServiceThatMakesHTTPCall();
}
function functionB() {
console.log('second');
return someServiceThatMakesHTTPCall();
}
来源:https://stackoverflow.com/questions/54901478/js-how-to-call-an-async-function-within-a-promise-then