How to group consecutive similar items of a collection?

有些话、适合烂在心里 提交于 2019-11-28 01:38:04

This does what you're looking for and is generic:

private static IEnumerable<IGrouping<int, T>> GroupConsecutive<T>(this IEnumerable<T> set, Func<T, T, bool> predicate)
{
    var i = 0;
    var k = 0;
    var ranges = from e in set
                 let idx = ++i
                 let next = set.ElementAtOrDefault(idx)
                 let key = (predicate(e, next)) ? k : k++
                 group e by key into g
                 select g;
    return ranges;
}

Usage:

var set = new List<bool>
            {
                true,
                false,
                false,
                false,
                true,
                true,
                false,
                false,
            };
var groups = set.GroupConsecutive((b1, b2) => (b1 == b2));
foreach (var g in groups)
{
    Console.WriteLine(g.Key);
    foreach (var b in g)
        Console.WriteLine("\t{0}", b);
}

Output:

0
        True
1
        False
        False
        False
2
        True
        True
3
        False
        False

While the code in the accepted answer meets the needs of the original question, it will fall over when handling IEnumerables of more complex objects (since the predicate will tend to throw an exception when comparing the last item in the enumerable with the "next" item [which, by definition, will always be null]).

This version handles more complex objects:

   public static IEnumerable<IGrouping<int, T>> GroupConsecutive<T>(this IEnumerable<T> set, Func<T, T, bool> predicate)
    {
        var i = 0;
        var k = 0;
        var ranges = from e in set
                     let idx = ++i
                     let next = set.ElementAtOrDefault(idx)
                     let key = next == null ? k : (predicate(e, next)) ? k : k++
                     group e by key into g
                     select g;
        return ranges;
    } 
last = null;
foreach (var option in list)
{
   if (last != option)
      newlist.Add(new Group(option, new[]));
   newlist.Last().Add(option);
   last = option;
}
public class GroupConsecutiveEqualItemsConverter : IValueConverter
{
    static readonly object UnsetValue = new object();

    public object Convert(object value, Type targetType, object parameter, CultureInfo culture)
    {
        IEnumerable source = value as IEnumerable;
        if (source == null) return DependencyProperty.UnsetValue;
        string propertyName = parameter as string;
        var result = new ObservableCollection<List<object>>();

        var notify = value as INotifyCollectionChanged;
        if (notify != null) notify.CollectionChanged += delegate { Reload(result, source, propertyName); };

        Reload(result, source, propertyName);
        return result;
    }

    public object ConvertBack(object value, Type targetType, object parameter, CultureInfo culture)
    {
        throw new NotSupportedException();
    }

    void Reload(ObservableCollection<List<object>> result, IEnumerable source, string propertyName)
    {
        result.Clear();
        object previous = UnsetValue;
        List<object> group = null;
        foreach (object i in source)
        {
            object current = UnsetValue;
            if (propertyName == null)
            {
                current = i;
            }
            else
            {
                try
                {
                    var property = i.GetType().GetProperty(propertyName);
                    if (property != null) current = property.GetValue(i, null);
                }
                catch (AmbiguousMatchException) { }
            }
            if (!object.Equals(previous, current))
            {
                if (group != null) result.Add(group);
                group = new List<object>();
            }
            group.Add(i);
            previous = current;
        }
        if (group != null && group.Count > 0) result.Add(group);
    }
}
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!