问题
I have the following columns in a dataframe which difference between each row is 0.012 s :
Time
0
0.012
0.024
0.036
0.048
0.060
0.072
0.084
0.096
0.108
I want to come up with intervals starting from beginning increasing by 0.030, so intervals or time window of every 0.03 later to be used in group by.
回答1:
You can try findInterval like
findInterval(df$Time, seq(min(df$Time), max(df$Time), 0.03))
#[1] 1 1 1 2 2 3 3 3 4 4
We can also use cut
breaks <- seq(min(df$Time), max(df$Time), 0.03)
cut(df$Time, c(breaks, Inf), labels = breaks, include.lowest = TRUE)
#[1] 0 0 0 0.03 0.03 0.03 0.06 0.06 0.09 0.09
data
df <- structure(list(Time = c(0, 0.012, 0.024, 0.036, 0.048, 0.06,
0.072, 0.084, 0.096, 0.108)), class = "data.frame", row.names = c(NA, -10L))
来源：https://stackoverflow.com/questions/57905792/how-to-cut-a-vector-or-column-into-intervals-in-r