Using str.split for pandas dataframe values based on parentheses location

问题

Let's say I have the following dataframe series df['Name'] column:

         Name
       'Jerry'
  'Adam (and family)'
'Paul and Hellen (and family):\n'
'John and Peter (and family):/n'

How would I remove all the contents in Name after the first parentheses?

df['Name']= df['Name'].str.split("'(").str[0] 

doesn't seem to work and I don't understand why?

The output I want is

         Name
       'Jerry'
        'Adam'
    'Paul and Hellen'
    'John and Peter'

so everything after the parentheses is deleted.

回答1:

Solution with split - is necessary escape ( by \:

df['Name']= df['Name'].str.split("\s+\(").str[0]
print (df)
               Name
0           'Jerry'
1             'Adam
2  'Paul and Hellen
3   'John and Peter

Solution with regex and replace:

df['Name']= df['Name'].str.replace("\s+\(.*$", "")
print (df)
               Name
0           'Jerry'
1             'Adam
2  'Paul and Hellen
3   'John and Peter

\s+\(.*$ means replace from optional whitespace, first ( to the end of string $ to "" - empty string.

回答2:

Use regular expression:

>>> import re
>>> str = 'Adam (and family)'
>>> result = re.sub(r"( \().*$", '', str)
>>> print result
Adam

来源：https://stackoverflow.com/questions/42205616/using-str-split-for-pandas-dataframe-values-based-on-parentheses-location