Perl regex with pipes

问题

I'm not exactly a perl monk, so if you could help me digest what does this regex(if it is one) do?

my $pathHere = "/some/path/to/file";
my $pathThere = "/some/path/";
$pathHere =~ s|$pathThere||;

Perl is not exactly my everyday tool, so I am quite shy on knowledge - I guess it subs the match to the var value, but guessing is not the way to go - the pipes throw me off...

Thanks

回答1:

In Perl you'd normally use the / as a delimiter in the regexp.

$pathHere =~ s/abc/def/;   # replace 'abc' with 'def'

However you can see that for paths, that's problematic, since you'd have to escape everything.

$pathHere =~ s/my\/path\/here/my\/newpath\/there/;  

Consequently Perl allows you to specify a different delimiter as the character after the 's', hence:

$pathHere =~ s|my/path/here|my/newpath/there|;

See the documentation for more information.

来源：https://stackoverflow.com/questions/31830613/perl-regex-with-pipes