问题
Right so I'm working on a python code and I get this type error, "TypeError: printE() missing 3 required positional arguments: 'emp2', 'emp3', and 'emp4'"
for emmp in employee:
print(printE(emmp))
def printE(emp1, emp2, emp3, emp4):
emp1 = "{}, {}, {}, {}".format(emp1[0], ' '.join(emp1[1:-2]))
emp2 = "{}, {}, {}, {}".format(emp2[1], ' '.join(emp2[2:-3]))
emp3 = "{}, {}, {}, {}".format(emp3[2], ' '.join(emp3[3]))
emp4 = "{}, {}, {}, {}".format(emp4[3], ' '.join(emp4[0:-1]))
print("{:10s} {:15s} {:5s} {:15s}".format(emp4[0], emp1[1], emp2[2], emp3[3]))
Any sort of help will be much appreciated!
回答1:
for emmp in employee:
print(printE(emmp))
as you say employee is tuple like
Case 1
employee = ('E1','E2'.....)
Note: when you iterator over tuple using for loop it gives you single employ E1 or next time E2 so on
And your function printE takes four arguments and you call it with the only single argument 'E1' or next time 'E2' so on.
So it gives you error that remaining argument are missing.
Case 2
if employee is tuple of tuple then look this example
employee = (('E1',10,"b10",20),('E1',10,"b10",20))
def printE(emp1, emp2, emp3, emp4):
""" do what ever you want to do with param meters """
return emp1 ,emp2 ,emp3, emp4
for emmp in employee:
print(printE(*emmp))
Output
('E1', 10, 'b10', 20)
('E1', 10, 'b10', 20)
回答2:
in a for loop, you will get one employee at a time. so the function is getting only one argument. The error is clear, that 3 arguments are missing. try passing the employees directly into the function
回答3:
printE method takes 4 arguments and in your loop your only giving one. Or if in loop 'emmp' is a list of four elements. Then try calling like 'printE(*emmp)'.
来源:https://stackoverflow.com/questions/45853466/missing-3-required-positional-arguments-python