Incrementing current date by 5 minutes in bash

问题

In my script I'm storing the current in date in a variable, however I would like the variable to store the date 5 minutes ahead.

29/10/2014-10:47:06 to 29/10/2014-10:52:06

Is there a quick and easy way to do this in Bash? Looking for a solution that would also work correctly if the time was 10:59:00 for example (recognising to enter the next hour).

I've found some Perl solutions but nothing for Bash.

回答1:

You can use the -d option:

$ date
mercredi 29 octobre 2014, 11:45:45 (UTC+0100)
$ date -d '5 mins'
mercredi 29 octobre 2014, 11:50:55 (UTC+0100)

And if you want to use a variable:

$ curr=$(date +%d/%m/%Y-%H:%M:%S)
$ echo $curr
29/10/2014-11:59:50
$ date -d "($cur) +5mins" +%d/%m/%Y-%H:%M:%S
29/10/2014-12:04:54

回答2:

you need to use -d option, with any user defined date:

 date -d '2014/10/29 10:58:06  5 minutes'
 Wed Oct 29 11:03:06 IST 2014

for current date

date -d '5 minutes'

回答3:

Have a look at date: date +%s gives you the seconds since 1.1.1970, add 5*60 and convert it back using date --date='@<newTime>'.

See man date in bash.

回答4:

In Bash, the following options are supported for date command:

 -a [-]sss.fff   Slowly adjust the time  by  sss.fff  seconds
                 (fff represents fractions of a second). This
                 adjustment can be positive or negative.  The
                 system's  clock  is  sped  up or slowed down
                 until  it  has  drifted  by  the  number  of
                 seconds  specified.  Only the super-user may
                 adjust the time.

So, use the following to add 5 mins (=300 seconds):

date -a 300

来源：https://stackoverflow.com/questions/26628392/incrementing-current-date-by-5-minutes-in-bash

标签

bash

date