Function returns None

爱⌒轻易说出口 提交于 2021-02-02 09:31:09

问题


After making an error then doing recursion i get None.

def getplayerinput():
    a = ["rock","paper","scissors"]
    plin = raw_input("Choose %s/%s/%s: " %(a[0], a[1], a[2]))
    print plin,'-first print'
    if plin not in a:
        print "Wrong input"
        getplayerinput()
    else:
        print plin,'-second print'
        return plin

for i in range(0,11):
    print getplayerinput()

If you input first 'rock' then 'cat' then 'paper' you will get a 'None'.


回答1:


You do not return anything once the input is not valid. Do this instead:

def getplayerinput():
    a = ["rock","paper","scissors"]
    plin = raw_input("Choose %s/%s/%s: " %(a[0], a[1], a[2]))
    print plin,'-first print'
    if plin not in a:
        print "Wrong input"
        return getplayerinput() # <- added return
    else:
        print plin,'-second print'
        return plin

for i in range(0,11):
    print getplayerinput()

Otherwise the recursion call will return something to a top level call, but that one just swallows the return value from the recursion call, since it doesn't pass it on via return.



来源:https://stackoverflow.com/questions/32793924/function-returns-none

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!