is there a way to specify a constructor for a groovy script?

问题

I have a groovy script called Foo.groovy, an instance of that script can be constructed using the following syntax:

def foo = new Foo()

i know if Foo.groovy looks like:

import groovy.transform.Field

@Field def bar

def someMethod() {
  //...
}

the following syntax:

def foo = new Foo(bar: 'baz')

will use some default constructor and actually set the bar field to baz, but let's say that i wanted to manipulate the passed value of bar to add an exclamation point at the end like so "${bar}!"

would like to be able to do something like the following (which doesn't work AFAIK):

import groovy.transform.Field

@Field def bar

Foo(args) {
  bar = "${args.bar}!"
}

def someMethod() {
  //...
}

Is there an idiomatic way to accomplish that in groovy?

回答1:

You may use setter method

(Foo.groovy):

import groovy.transform.Field

@Field def bar

void setBar(def bar){
    this.bar = "${bar}!"
    println "Setter is executed. ${bar} -> ${this.bar}"
}

And if the calling party will look like

import Foo
def foo = new Foo(bar: 'baz')
println foo.bar

the following result appears:

Setter is executed. baz -> baz!
baz!

回答2:

Any free variable in the main body of the script can be satisfied out of the Binding object. It works pretty much like a map because it has a map-based constructor and has overloaded getProperty and setProperty. http://docs.groovy-lang.org/latest/html/gapi/groovy/lang/Binding.html

Main script:

def binding = new Binding(bar: 'baz')
def foo = new Foo(binding)
foo.run()

Foo.groovy:

someMethod(bar + '!')

def someMethod(baz) { // bar/baz value must be passed in
  // do something with baz
}

I have not tried this out, but it should be easy enough to plug it into Groovy Console and see what happens.

来源：https://stackoverflow.com/questions/54831615/is-there-a-way-to-specify-a-constructor-for-a-groovy-script

标签

groovy