Java 8 ISO 8601 Interval syntax with wildcard field(s)

问题

I need to parse a time interval expression similar to ISO 8601 syntax, only allowing wildcard for fields; and storing the start and end into two LocalDateTime objects. My Interval would then have APIs to compare to a third LocalDateTime or OffsetDateTime to check if it falls inside or outside of the interval.

E.g.: when parsing "****-**-**T00:00:00Z/****-**-**T11:55:00Z", the date of the start and end instant should be the day of the start program execution (ignoring running into the next day problem). How can I parse an expression like this?

EDIT: to make it clear, if I run it today, it should be equivalent of parsing "2016-04-06T00:00:00Z/2016-04-06T11:55:00Z".

回答1:

I don't think there is a way to use wildcards when parsing a string with java.time. A not so good-looking hack would be to replace the * by 1: that should not produce any unparseable date. You can then ignore the date content.

For example:

String input = "****-**-01T00:00:00Z/****-04-**T11:55:00Z";
String[] dates = input.replace("*", "1").split("/");
ZonedDateTime zdt1 = ZonedDateTime.parse(dates[0]);
ZonedDateTime zdt2 = ZonedDateTime.parse(dates[1]);

LocalDate day = LocalDate.now(); //or whatever date you like

LocalDateTime start = zdt1.toLocalTime().atDate(day);
LocalDateTime end = zdt2.toLocalTime().atDate(day);

System.out.println(start + " / " + end);

来源：https://stackoverflow.com/questions/36456242/java-8-iso-8601-interval-syntax-with-wildcard-fields