问题
Is there a way to do a java ternary operation without doing an assignment or way to fake the assingment?
I like how succinct ternary code looks when doing a bunch of if/then/elses.
I\'m hoping to be able to call one of two void functions based on a boolean algebra statement.
Something like:
(bool1 && bool2) ? voidFunc1() : voidFunc2();
My functions are of return type void
, so if there is a way to fake this in an assignment to make it work, then I\"m okay with that... I would like to see how to do it though :)
回答1:
Nope you cannot do that. The spec says so.
The conditional operator has three operand expressions. ? appears between the first and second expressions, and : appears between the second and third expressions.
The first expression must be of type boolean or Boolean, or a compile-time error occurs.
It is a compile-time error for either the second or the third operand expression to be an invocation of a void method.
[EDIT]
Since you asked about reflection, here's a solution. I'm not recommending this. I'm posting it only because you asked.
public class MyCall
{
public void a(){System.out.println("a");}
public void b(){System.out.println("b");}
public static void main(String... args)
{
new MyCall().go();
}
public void go()
{
Class<? extends MyCall> class1 = this.getClass();
Method aMethod = class1.getMethod("b", null);
Method bMethod = class1.getMethod("a", null);
Object fake = false ? aMethod.invoke(this, null) : bMethod.invoke(this, null);
Object fake2 = true ? aMethod.invoke(this, null) : bMethod.invoke(this, null);
}
}
At the end of the day you've got to ask yourself if being succint improves your code's readability (think for-each loop). None of these solutions improve the code's readability IMHO. If I were you I'd rather go with this.
if(condition)
a();
else
b();
I'm actually for including braces even when loops only contain a single line, but since you're going after crisp code, the snippet above should do.
回答2:
No, you can't do this like this.
You can prefer this style if do not like make it more statements.
if(bool1 && bool2) voidFunc1(); else voidFunc2();
In ternary operator, Operands are required to be non-void expressions; i.e. they must produce some actual value.
回答3:
If you really-really want to use ternany operation, then there is one hack. BUT this is very bad code, intended only for showing abilities of language. I would never recommend to put this code in production or even show to your friends.
int dummy = (bool1 && bool2) ? new Object(){
public int hashCode() {
yourFunction1();
// ...
yourFunctionN();
return 0;
};
}.hashCode() : new Object(){
public int hashCode() {
yourAnotherFunction1();
// ...
yourAnotherFunctionN();
return 0;
};
}.hashCode();
回答4:
Is there a way to do a java ternary operation without doing an assignment or way to fake the assignment?
OK, so when you write a statement like this:
(bool1 && bool2) ? voidFunc1() : voidFunc2();
there are two distinct problems with the code:
The 2nd and 3rd operands of a conditional expression1 cannot be calls to void methods. Reference: JLS 15.25.
An expression is not a statement, unless it is either and assignment expression OR a method call OR a object creation. Reference: JLS 14.8.
In fact, the second of these problems is a syntax error and I would expect any mainstream Java compilers to report it instead of the first problem. The first problem would only reveal itself if you did something like this:
SomeType dummy = (bool1 && bool2) ? voidFunc1() : voidFunc2();
or
gobble((bool1 && bool2) ? voidFunc1() : voidFunc2());
where gobble
is a method that does nothing ... except "consume" the value of its argument.
AFAIK, there is no context in which the original expression is acceptable.
1 - "Conditional expression" is the primary term used for this construct in the Java Language Specification. It is called the "ternary conditional operator" in Oracle Java Tutorial.
来源:https://stackoverflow.com/questions/15977031/java-ternary-without-assignment