Python Asyncio - Pythonic way of waiting until condition satisfied

问题

I need to wait until a certain condition/equation becomes True in a asynchronous function in python. Basically it is a flag variable which would be flagged by a coroutine running in asyncio.create_task(). I want to await until it is flagged in the main loop of asyncio. Here's my current code:

import asyncio
flag = False

async def bg_tsk():
    await asyncio.sleep(10)
    flag = True

async def waiter():
    asyncio.create_task(bg_tsk())
    await asyncio.sleep(0)
    # I find the below part unpythonic
    while not flag:
        await asyncio.sleep(0.2)

asyncio.run(waiter())

Is there any better implementation of this? Or is this the best way possible? I have tried using 'asyncio.Event', but it doesnt seem to work with 'asyncio.create_task()'.

回答1:

Using of asyncio.Event is quite straightforward. Sample below.

Note: Event should be created from inside coroutine for correct work.

import asyncio


async def bg_tsk(flag):
    await asyncio.sleep(3)
    flag.set()


async def waiter():
    flag = asyncio.Event()
    asyncio.create_task(bg_tsk(flag))
    await flag.wait()
    print("After waiting")


asyncio.run(waiter())

来源：https://stackoverflow.com/questions/65352682/python-asyncio-pythonic-way-of-waiting-until-condition-satisfied