问题
By default when you use "ActivateItem(new Control());" your control is loaded into a ContentControl which with the name ActiveItem, fro example. . If I have multiple content controls on my page how would I load controls into them whilst retaining the ability to use the default functionality of being able to load controls into the the active item control.
for example I want to have a login control to be loaded into the Login ContentControl, and when a user successfully login I want a new control to be loaded into the ActiveItem ContentControl.
Thanx in advance.
回答1:
If the ViewModel that gets binded to the UI contains a property with the name that matches a content control. The Content control view automatically gets resolved the the view supported by this property, provided this property itself is a ViewModel type and has been registed with Ioc container. For example
<ContentControl x:Name="LoginStatus"></ContentControl>
If there is a property LoginStatus on the main ViewModel (LoginStatus property itself is a ViewModel). The content control would correctly get rendered with the appropriate view.
回答2:
You should have a look at Screen Conductors. See here.
来源：https://stackoverflow.com/questions/6185675/how-do-i-load-controls-in-different-contentcontrols-of-a-shell-using-caliburnmic