Rust: Vec<Vec<T>> into Vec<T>

问题

let a = vec![ vec![1, 2], vec![3, 4], vec![5, 6] ];

How can I gather into a single Vec all the values contained in all the Vecs in a ?

回答1:

You can use the flatten operator to remove the nesting of the vectors.

The following example is taken from the link.

let data = vec![vec![1, 2, 3, 4], vec![5, 6]];
let flattened = data.into_iter().flatten().collect::<Vec<u8>>();
assert_eq!(flattened, &[1, 2, 3, 4, 5, 6]);

回答2:

Steve's answer is correct, but you should also know about flat_map -- there's a good chance that that's what you really want to use, that it would make your code simpler and faster. You probably don't need to ever create a Vec of Vecs -- just an Iterator of Iterators that you flat_map and then collect.

来源：https://stackoverflow.com/questions/61287299/rust-vecvect-into-vect