问题
I currently use docker for my backend, and when I first start them up with
docker-compose up
I get log outputs of all 4 dockers at once, so I can see how they are interacting with each other when a request comes in. Looking like this, one request going from nginx to couchdb
The issue is now that I am running on GCE with load balancing, when a new VM spins up, it auto starts the dockers and runs normally, I would like to be able to access a load balanced VM and view the live logs, but I can not get docker to allow me this style, when I use logs, it gives me normal all white font with no label of where it came from.
Using
docker events
does nothing, it won't return any info.
tldr; what is the best way to obtain a view, same as the log output you get when running "docker-compose up"
回答1:
If using docker-compose, you use
docker-compose logs --tail=0 --follow
instead of
docker logs --tail=0 --follow
This will get the output I was originally looking for.
回答2:
You can see the logs for all running containers with
docker ps -q | xargs -L 1 docker logs
In theory this might work for the --follow
too if xargs is ran with -P <count>
, where the count is higher than the number of running containers.
回答3:
I use a variation of this to live tail (--follow) all logs and indicate which log is tailing at the time. This bash includes both stdout and stderr. Note you may need to purge the /tmp dir of *.{log,err} afterwards.
for c in $(docker ps -a --format="{{.Names}}")
do
docker logs -f $c > /tmp/$c.log 2> /tmp/$c.err &
done
tail -f /tmp/*.{log,err}
Hope this helps. Logging has become so problematic these days, and other get-off-my-lawn old man rants...
回答4:
If you are using Docker Swarm, you can find your services by
docker service ls
Grap the id, and then run
docker service logs $ID -f
if the service is defined with tty: true, then you must run with the --raw flag. Notice, this wont tell you which container is giving the outputted log entry.
来源:https://stackoverflow.com/questions/36756751/view-logs-for-all-docker-containers-simultaneously