How to override WebSocket send() method

问题

I'm trying to override the WebSocket.send() method. My objective is being able to fuzz the sent data to test robustness of the server implementation.

I'm adopting this approach:

// OVERRIDE WEBSOCKET SEND METHOD
WebSocket.prototype.oldSend = WebSocket.prototype.send;

WebSocket.prototype.send = function(data) {
     console.log("ws: sending data");
     WebSocket.prototype.oldSend(data);
};

This fails when the WebSocket.prototype.oldSend(data) command is called the first time, with the error: Failed to send: 'send' called on an object that does not implement interface WebSocket.

Anybody if it is possible to override the built-in websocket send method(), or what else I'm missing?

TIA

回答1:

How about:

WebSocket.prototype.oldSend = WebSocket.prototype.send;

WebSocket.prototype.send = function(data) {
     console.log("ws: sending data");
     WebSocket.prototype.oldSend.apply(this, [data]);
};

JSFiddle

回答2:

As far as I know, you can't override WebSocket.send() implementation, as it is read-only in most of browser.

All you can do is something like:

var mysend = function(data) {
    console.log("ws: sending data");
    WebSocket.send(data);
};

which should do the trick anyway, without messing with prototypes.

来源：https://stackoverflow.com/questions/40341197/how-to-override-websocket-send-method