How to get start and end of previous month in VB

旧时模样 提交于 2020-12-27 19:01:01

问题


Im trying to create some VB code that will get the start and end of the previous month. Im able to the current month which is just:

Month(DateValue(Now))

which would return 3. From there I can take away 1 to give me 2 meaning February. This is fine but what about when I Im in January and I repeat this and it gives me zero - my code will fail. Any one know how to get the previous months start and end day then?

Thanks


回答1:


The first day of the previous month is always 1, to get the last day of the previous month, use 0 with DateSerial:

''Today is 20/03/2013 in dd/mm/yyyy
DateSerial(Year(Date),Month(Date),0) = 28/02/2013 
DateSerial(Year(Date),1,0) = 31/12/2012 

You can get the first day from the above like so:

LastDay = DateSerial(Year(Date),Month(Date),0)
FirstDay = LastDay-Day(LastDay)+1

See also: How to caculate last business day of month in VBScript




回答2:


I have similar formula for the First and Last Day

The First Day of the month

FirstDay = DateSerial(Year(Date),Month(Date),1)

The zero Day of the next month is the Last Day of the month

LastDay = DateSerial(Year(Date),Month(Date)+ 1,0) 



回答3:


firstDay = DateSerial(Year(DateAdd("m", -1, Now)), Month(DateAdd("m", -1, Now)), 1)
lastDay = DateAdd("d", -1, DateSerial(Year(Now), Month(Now), 1))

This is another way to do it, but I think Remou's version looks cleaner.




回答4:


Try this

First_Day_Of_Previous_Month = New Date(Today.Year, Today.Month, 1).AddMonths(-1)

Last_Day_Of_Previous_Month = New Date(Today.Year, Today.Month, 1).AddDays(-1)



回答5:


This works reliably for me in my main sub.

Dim defDate1 As Date, defDate2 As Date

'** Set default date range to previous month
defDate1 = CDate(Month(Now) & "/1/" & Year(Now))
defDate1 = DateAdd("m", -1, defDate1)
defDate2 = DateAdd("d", -1, DateAdd("m", 1, defDate1))



回答6:


Try this to get the month in number form:

Month(DateAdd("m", -3, Now))

It will give you 12 for December.

So in your case you would use Month(DateAdd("m", -1, Now)) to just subract one month.




回答7:


Just to add something to what @Fionnuala Said, The below functions can be used. These even work for leap years.

'If you pass #2016/20/01# you get #2016/31/01#
Public Function GetLastDate(tempDate As Date) As Date
    GetLastDate = DateSerial(Year(tempDate), Month(tempDate) + 1, 0)
End Function

'If you pass #2016/20/01# you get 31
Public Function GetLastDay(tempDate As Date) As Integer
    GetLastDay = Day(DateSerial(Year(tempDate), Month(tempDate) + 1, 0))
End Function



回答8:


Public Shared Function GetFOMPrev(ByVal tdate As Date) As Date
    Return tdate.AddDays(-(tdate.Day - 1))
End Function

Public Shared Function GetEOMPrev(ByVal tdate As Date) As Date
    Return tdate.AddDays(-tdate.Day)
End Function

Usage:

'Get End of Month of Previous Month - Pass today's date
EOM = GetEOMPrev(Date.Today)

'Get First of Month of Previous Month - Pass date just calculated
FOM = GetFOMPrev(EOM)


来源:https://stackoverflow.com/questions/15430035/how-to-get-start-and-end-of-previous-month-in-vb

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