The output of cout << 1 && 0; [closed]

Question

I don't understand why the below code prints 1.

1 && 0 is not the same as true && false -> false?

Why doesn't this print 0?

#include <iostream>

using namespace std;

int main(){
    cout << 1 && 0;
    return 0;
}

Answer 1

It's all about Operator Precedence.

The Overloaded Bitwise Left Shift Operator operator<<(std::basic_ostream) has a higher priority than the Logical AND Operator &&.

#include <iostream>
int main() {
    std::cout << (1 && 0);
    return 0;
}

If you are not 146% sure about the priority of an operator, do not hesitate to use brackets. Most modern IDEs will tell you if you don't need to use them.