问题
If I have 8 packed 32-bit floating point numbers (__m256
), what's the fastest way to extract the horizontal sum of all 8 elements? Similarly, how to obtain the horizontal maximum and minimum? In other words, what's the best implementation for the following C++ functions?
float sum(__m256 x); ///< returns sum of all 8 elements
float max(__m256 x); ///< returns the maximum of all 8 elements
float min(__m256 x); ///< returns the minimum of all 8 elements
回答1:
Quickly jotted down here (and hence untested):
float sum(__m256 x) {
__m128 hi = _mm256_extractf128_ps(x, 1);
__m128 lo = _mm256_extractf128_ps(x, 0);
lo = _mm_add_ps(hi, lo);
hi = _mm_movehl_ps(hi, lo);
lo = _mm_add_ps(hi, lo);
hi = _mm_shuffle_ps(lo, lo, 1);
lo = _mm_add_ss(hi, lo);
return _mm_cvtss_f32(lo);
}
For min/max, replace _mm_add_ps
and _mm_add_ss
with _mm_max_*
or _mm_min_*
.
Note that this is a lot of work for a few operations; AVX isn't really intended to do horizontal operations efficiently. If you can batch up this work for multiple vectors, then more efficient solutions are possible.
回答2:
While Stephen Canon's answer is probably ideal for finding the horizontal maximum/minimum I think a better solution can be found for the horizontal sum.
float horizontal_add (__m256 a) {
__m256 t1 = _mm256_hadd_ps(a,a);
__m256 t2 = _mm256_hadd_ps(t1,t1);
__m128 t3 = _mm256_extractf128_ps(t2,1);
__m128 t4 = _mm_add_ss(_mm256_castps256_ps128(t2),t3);
return _mm_cvtss_f32(t4);
}
回答3:
I tried to write code that avoids mixing avx and non-avx instructions and the horizontal sum of an avx register containing floats can be done avx-only by
- 1x
vperm2f128
, - 2x
vshufps
and - 3x
vaddps
,
resulting in a register where all entries contain the sum of all elements in the original register.
// permute
// 4, 5, 6, 7, 0, 1, 2, 3
// add
// 0+4, 1+5, 2+6, 3+7, 4+0, 5+1, 6+2, 7+3
// shuffle
// 1+5, 0+4, 3+7, 2+6, 5+1, 4+0, 7+3, 6+2
// add
// 1+5+0+4, 0+4+1+5, 3+7+2+6, 2+6+3+7,
// 5+1+4+0, 4+0+5+1, 7+3+6+2, 6+2+7+3
// shuffle
// 3+7+2+6, 2+6+3+7, 1+5+0+4, 0+4+1+5,
// 7+3+6+2, 6+2+7+3, 5+1+4+0, 4+0+5+1
// add
// 3+7+2+6+1+5+0+4, 2+6+3+7+0+4+1+5, 1+5+0+4+3+7+2+6, 0+4+1+5+2+6+3+7,
// 7+3+6+2+5+1+4+0, 6+2+7+3+4+0+5+1, 5+1+4+0+7+3+6+2, 4+0+5+1+6+2+7+3
static inline __m256 hsums(__m256 const& v)
{
auto x = _mm256_permute2f128_ps(v, v, 1);
auto y = _mm256_add_ps(v, x);
x = _mm256_shuffle_ps(y, y, _MM_SHUFFLE(2, 3, 0, 1));
x = _mm256_add_ps(x, y);
y = _mm256_shuffle_ps(x, x, _MM_SHUFFLE(1, 0, 3, 2));
return _mm256_add_ps(x, y);
}
Obtaining the value is then easy by using _mm256_castps256_ps128
and _mm_cvtss_f32
:
static inline float hadd(__m256 const& v)
{
return _mm_cvtss_f32(_mm256_castps256_ps128(hsums(v)));
}
I did some basic benchmarks against the other solutions with __rdtscp
and did not find one to be superior in terms of mean cpu cycle count on my Intel i5-2500k.
Looking at the Agner Instruction Tables I found (for Sandy-Bridge processors):
µops lat. 1/tp count
this:
vperm2f128 1 2 1 1
vaddps 1 3 1 3
vshufps 1 1 1 2
sum 6 13 6 6
Z boson:
vhaddps 3 5 2 2
vextractf128 1 2 1 1
addss 1 3 1 1
sum 8 15 6 4
Stephen Canon:
vextractf128 1 2 1 1
addps 1 3 1 2
movhlps 1 1 1 1
shufps 1 1 1 1
addss 1 3 1 1
sum 8 13 6 6
where to me (due to the values being rather similar) none is clearly superior (as I cannot forsee whether instruction count, µop count, latency or throughput matters most).
edit, note: The potential problem I assumed to exist in the following is not true.
I suspected, that -if having the result in the ymm register is sufficient- my hsums
could be useful as it doesn't require vzeroupper
to prevent state switching penalty and can thus interleave / execute concurrently with other avx computations using different registers without introducing some kind of sequence point.
回答4:
union ymm {
__m256 m256;
struct {
__m128 m128lo;
__m128 m128hi;
};
};
union ymm result = {1,2,3,4,5,6,7,8};
__m256 a = {9,10,11,12,13,14,15,16};
result.m256 = _mm256_add_ps (result.m256, a);
result.m128lo = _mm_hadd_ps (result.m128lo, result.m128hi);
result.m128lo = _mm_hadd_ps (result.m128lo, result.m128hi);
result.m128lo = _mm_hadd_ps (result.m128lo, result.m128hi);
来源:https://stackoverflow.com/questions/13879609/horizontal-sum-of-8-packed-32bit-floats