openURL from App Extension

独自空忆成欢 提交于 2019-11-27 22:11:35
Laurence Fan

you may use this code:

[self.extensionContext openURL:url completionHandler:^(BOOL success) {
        NSLog(@"fun=%s after completion. success=%d", __func__, success);
    }];

the API document: openURL:completionHandler:

you could also refer to this question: openURL not work in Action Extension

Accepted solution only works in Today extensions, a working solution in Swift 3.1 (tested in iOS10) for other extension-types:

You need to create your own URL Scheme, then add this function to your ViewController and call it with openURL("myScheme://myIdentifier")

//  Function must be named exactly like this so a selector can be found by the compiler!
//  Anyway - it's another selector in another instance that would be "performed" instead.
func openURL(_ url: URL) -> Bool {
    var responder: UIResponder? = self
    while responder != nil {
        if let application = responder as? UIApplication {
            return application.perform(#selector(openURL(_:)), with: url) != nil
        }
        responder = responder?.next
    }
    return false
}

In iOS 11 it seems that you can use UIApplication.sharedApplication.openURL in extensions without the problem.

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