python日记—函数生成器

# 求斐波那数列 ：1,1,2,3,5,8,13,21,34......
'''
函数生成器,关键字 yield
'''

def get_fbn(max_num):
    a = 0
    b = 1
    c = list()
    while b <= max_num:
        tmp = a
        a = b
        b += tmp
        c.append(a)
        yield c  # 返回c,并且暂停当前函数

if __name__ == '__main__':
    func = get_fbn(10)  # 下面每执行一次func，则继续从get_fbn上次暂停位置继续执行
    print(func.__next__()) # 输出：[1]
    print('xxxxxxx')
    print(func.__next__()) # 输出：[1, 1]
    print('xxxxxxx')
    print(func.__next__()) # 输出：[1, 1, 2]
    print('xxxxxxx')
    print(func.__next__()) # 输出：[1, 1, 2, 3]
    print('xxxxxxx')
    print(func.__next__()) # 输出：[1, 1, 2, 3, 5]
    print('xxxxxxx')
    print(func.__next__()) # 输出：[1, 1, 2, 3, 5, 8]

 

来源：oschina

链接：https://my.oschina.net/jugier/blog/4284512