问题
I have a file with a single unicode symbol.
The file is encoded in UTF-8.
It contains a single symbol represented as 4 bytes.
https://www.fileformat.info/info/unicode/char/1f60a/index.htm
F0 9F 98 8A
When I read the file I get two symbols/chars.
The program below prints
?
2
?
?
55357
56842
======================================
��
16
&
======================================
?
2
?
======================================
Is this normal... or a bug? Or am I misusing something?
How do I get that single emoji symbol in my code?
EDIT: And also... how do I escape it for XML?
import java.io.BufferedReader;
import java.io.FileInputStream;
import java.io.InputStreamReader;
public class Test008 {
public static void main(String[] args) throws Exception{
BufferedReader in = new BufferedReader(
new InputStreamReader(
new FileInputStream("D:\\DATA\\test1.txt"), "UTF8"));
String s = "";
while ((s = in.readLine()) != null) {
System.out.println(s);
System.out.println(s.length());
System.out.println(s.charAt(0));
System.out.println(s.charAt(1));
System.out.println((int)(s.charAt(0)));
System.out.println((int)(s.charAt(1)));
String z = org.apache.commons.lang.StringEscapeUtils.escapeXml(s);
String z3 = org.apache.commons.lang3.StringEscapeUtils.escapeXml(s);
System.out.println("======================================");
System.out.println(z);
System.out.println(z.length());
System.out.println(z.charAt(0));
System.out.println("======================================");
System.out.println(z3);
System.out.println(z3.length());
System.out.println(z3.charAt(0));
System.out.println("======================================");
}
in.close();
}
}
回答1:
Yes normal, the Unicode symbol is 2 UTF-16 chars (1 char is 2 bytes).
int codePoint = s.codePointAt(0); // Your code point.
System.out.printf("U+%04X, chars: $d%n", codePoint, Character.charCount(cp));
U+F09F988A, chars: 2
After comments
Java, using a Stream:
public static String escapeToAsciiHTML(String s) {
StringBuilder sb = new StringBuilder();
s.codePoints().forEach(cp -> {
if (cp < 128) {
sb.append((char) cp);
} else{
sb.append("&#").append(cp).append(";");
}
});
return sb.toString();
}
回答2:
StringEscapeUtils is broken. Don't use it. Try NumericEntityEscaper.
Or, better yet, as apache commons libraries tend to be bad API** and broken*** anyway, guava*'s XmlEscapers
java is unicode, yes, but 'char' is a lie. 'char' does not represent characters; it represents a single, unsigned 16 bit number. The actual method to get a character out of, say, a j.l.String
object isn't charAt
, which is a misnomer; it's codepointAt
, and friends.
This (char being a fakeout) normally doesn't matter; most actual characters fit in the 16-bit char
type. But when they don't, this matters, and that emoji doesn't fit. In the unicode model used by java and the char
type, you then get 2 char values (representing a single unicode character). This pair is called a 'surrogate pair'.
Note that the right methods tend to work in int
(you need the 32 bits to represent one single unicode symbol, after all).
*) guava has its own issues, by being aggressively not backwards compatible with itself, it tends to lead to dependency hell. It's a pick your poison kind of deal, unfortunately.
**) Utils-anything is usually a sign of bad API design; 'util' is almost meaningless as a term and usually implies you've broken the object oriented model. The right model is of course to have an object representing the process of translating data in one form (say, a raw string) to another (say, a string that can be dumped straight into an XML file, escaped and well) - and such a thing would thus be called an 'escaper', and would live perhaps in a package named 'escapers' or 'text'. Later editions of apache libraries, as well as guava, fortunately 'fixed' this.
***) As this very example shows, these APIs often don't do what you want them to. Note that apache is open source; if you want these APIs to be better, they accept pull requests :)
来源:https://stackoverflow.com/questions/63133697/java-read-utf-8-file-with-a-single-emoji-symbol