问题
I have a struct with a lifetime:
struct HasLifetime<'a>( /* ... */ );
There is there is an implementation of the trait Foo
:
impl<'a, 'b: 'a> Foo for &'a mut HasLifetime<'b> { }
I want to implement the following function:
fn bar_to_foo<'a, 'b: 'a>(bar: &'a mut Lifetime<'b>) -> impl Foo {
bar
}
This won't compile because the returned impl
is only valid for 'a
. However, specifying impl Foo + 'a
results in:
error[E0909]: hidden type for `impl Trait` captures lifetime that does not appear in bounds
--> src/main.rs:7:60
|
7 | fn bar_to_foo<'a, 'b: 'a>(bar: &'a mut HasLifetime<'b>) -> impl Trait + 'a {
| ^^^^^^^^^^^^^^^
|
note: hidden type `&'a mut HasLifetime<'b>` captures the lifetime 'b as defined on the function body at 7:1
--> src/main.rs:7:1
|
7 | fn bar_to_foo<'a, 'b: 'a>(bar: &'a mut HasLifetime<'b>) -> impl Trait + 'a {
| ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
The seemingly equivalent function with a boxed trait object compiles:
fn bar_to_foo<'a, 'b: 'a>(bar: &'a mut Lifetime<'b>) -> Box<Foo + 'a> {
Box::new(bar)
}
How can I define bar_to_foo
with impl Trait
?
Playground link
回答1:
You need to indicate that the returned value is built upon multiple lifetimes. However, you can't use multiple lifetime bounds with impl Trait
, and attempting to do so doesn't have a useful error message.
There's a trick you can use that involves creating a dummy trait that has a lifetime parameter:
trait Captures<'a> {}
impl<'a, T: ?Sized> Captures<'a> for T {}
fn bar_to_foo<'a, 'b: 'a>(bar: &'a mut HasLifetime<'b>) -> impl Trait + Captures<'b> + 'a {
bar
}
Thankfully, this only occurs when the "hidden" lifetime is invariant, which occurs because the reference is mutable.
来源:https://stackoverflow.com/questions/50547766/how-can-i-get-impl-trait-to-use-the-appropriate-lifetime-for-a-mutable-reference