Python - How to break while loop after empty value in a int turning input? [duplicate]

问题

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Asking the user for input until they give a valid response (20 answers)

Closed 3 years ago.

I want to make the while loop break when empty input is typed. I know that the error is due to the int function because it cant turn to integer an empty input but how can i do what i'm trying to write?

while True:
    numb = int(input("number"))
    if numb % 2 == 0:
        print("this number is even")
    elif numb % 2 != 0:
        print("this number is odd")
    elif numb == '':
        break

回答1:

This would work:

while True:
    try:
        numb = int(input("number"))
    except ValueError:
        break
    if numb % 2 == 0:
        print("this number is even")
    elif numb % 2 != 0:
        print("this number is odd")

Just handle the exception if the input cannot be converted into an integer. Now, any input that is not an integer would terminate the loop.

来源：https://stackoverflow.com/questions/41299440/python-how-to-break-while-loop-after-empty-value-in-a-int-turning-input