To process a folder with xlsx files with openpyxl module

问题

I have folder ('rogaikopyta') with 1 000 files in xlsx format. I need to extract the data form each of these files (B2 and D2 cells) and print them in ordered consequence in one xlsx file. The original code is:

import openpyxl

import os

import pathlib

from openpyxl import load_workbook, Workbook

path = 'C:/Users/User/Documents/Visual Studio 2017/DjangoWebProject1/DjangoWebProject1/app/rogaikopyta'

for file in os.listdir(path):

wb=load_workbook(os.path.join(path,file), read_only=True)

ws=wb.active

wb2 = Workbook(write_only=True)

ws2 = wb2.create_sheet()

for row in ws.iter_rows(min_col=2, max_col=4, min_row=2, max_row=2, values_only=True):

    ws2.append([row[0], row[-1]])

wb2.save("output.xlsx")

It gives a loooot of errors, I suppose, concerning each of the xlsx files!

Like this:

Exception ignored in:

Traceback (most recent call last):

File "C:\Users\User\PycharmProjects\untitled3\venv\lib\site-packages\openpyxl\worksheet_write_only.py", line 74, in _write_rows

pass

File "C:\Users\User\AppData\Local\Programs\Python\Python37-32\lib\contextlib.py", line 119, in exit

next(self.gen)

File "C:\Users\User\PycharmProjects\untitled3\venv\lib\site-packages\et_xmlfile\xmlfile.py", line 50, in element

self._write_element(el)

File "C:\Users\User\PycharmProjects\untitled3\venv\lib\site-packages\et_xmlfile\xmlfile.py", line 50, in element

self._write_element(el)

File "C:\Users\User\PycharmProjects\untitled3\venv\lib\site-packages\et_xmlfile\xmlfile.py", line 78, in _write_element

self._file.write(xml)

ValueError: write to closed file

And it bothers me a lot! What is goin on with this code?

回答1:

You should probably read up on the os module and the pathlib module, as well as checking that your code is suitable for the more recent versions of openpyxl.

os.listdir(path) returns a list of files in a folder so the following should see you on your way

from openpyxl import load_workbook, Workbook
target_wb = Workbook()
target_ws = wb.active

for file in os.listdir(path):
    wb = load_workbook(os.path.join(path, file), read_only=True)
    ws = wb.active
    for row in ws.iter_rows(min_col=2, max_col=4, min_row=2, max_row=2, values_only=True):
         target_ws.append([row[0], row[-1])
target_wb.save("output.xlsx")

回答2:

Your code now looks like:

import openpyxl

import os

import pathlib

from openpyxl import load_workbook, Workbook

path = 'C:/Users/User/Documents/Visual Studio 2017/DjangoWebProject1/DjangoWebProject1/app/rogaikopyta'

for file in os.listdir(path):

wb=load_workbook(os.path.join(path,file), read_only=True)

ws=wb.active

wb2 = Workbook(write_only=True)

ws2 = wb2.create_sheet()

for row in ws.iter_rows(min_col=2, max_col=4, min_row=2, max_row=2, values_only=True):

    ws2.append([row[0],row[-1]])

wb2.save("output.xlsx")

But still it gives an access error, refering to the 1000 files:

Exception ignored in:

Traceback (most recent call last):

File "C:\Users\User\PycharmProjects\untitled3\venv\lib\site-packages\openpyxl\worksheet_write_only.py", line 74, in _write_rows

pass

File "C:\Users\User\AppData\Local\Programs\Python\Python37-32\lib\contextlib.py", line

119, in exit next(self.gen)

File "C:\Users\User\PycharmProjects\untitled3\venv\lib\site-packages\et_xmlfile\xmlfile.py", line 50, in element self._write_element(el)

File "C:\Users\User\PycharmProjects\untitled3\venv\lib\site-packages\et_xmlfile\xmlfile.py", line 78, in _write_element self._file.write(xml)

ValueError: write to closed file

Exception ignored in: Traceback (most recent call last):

File "C:\Users\User\PycharmProjects\untitled3\venv\lib\site-packages\openpyxl\worksheet_write_only.py", line 74, in _write_rows pass

If I put: for row in ws.iter_rows(min_col=2, max_col=4, min_row=2, max_row=2, values_only=True):

ws2.append([row[0],row[-1]])
wb2.save("output.xlsx")

it gives the result for only one cycle, i.e. for only one file xlsx, i need for all 1000 files in the folder. Can you please suggest what is going on?

来源：https://stackoverflow.com/questions/62284979/to-process-a-folder-with-xlsx-files-with-openpyxl-module