sum value of a 3rd row and divide rows accordingly

问题

I have a file as below with n number of rows, I want to total it's sum(based on 3rd column) and distribute rows accordingly in 3 different files(based on sum of each)

For example- if we sum all the 3rd column values it's total is coming as 516 and if we divide it by 3 it is 172.

So i want to add a rows to a file so it doesn't exceed 172 mark, same with the 2nd file and rest all rows should move to the third file.

Input file

a aa 10
b ab 15
c ac 17
a dy 30
y ae 12
a dl 34
a fk 45
l ah 56
o aj 76 
l ai 12 
q al 09
d pl 34
e ik 30
f ll 10
g dl 15 
h fr 17
i dd 23
j we 27
k rt 12
l yt 13
m tt 19

expected output

file1(total -163)


a   aa  10
b   ab  15
c   ac  17
a   dy  30
y   ae  12
a   dl  34
a   fk  45

file2 (total-153)

l   ah  56
o   aj  76
l   ai  12
q   al  9

file3 (total - 200)

d   pl  34
e   ik  30
f   ll  10
g   dl  15
h   fr  17
i   dd  23
j   we  27
k   rt  12
l   yt  13
m   tt  19

回答1:

Could you please try following, written and tested with shown samples in GNU awk.

awk '
FNR==NR{
  sum+=$NF
  next
}
FNR==1{
  count=sum/3
}
{
  curr_sum+=$NF
}
(curr_sum>=count || FNR==1) && fileCnt<=2{
  close(out_file)
  out_file="file" ++fileCnt
  curr_sum=$NF
}
{
  print > (out_file)
}'   Input_file  Input_file

Explanation: Adding detailed explanation for above.

awk '                                               ##Starting awk program from here.
FNR==NR{                                            ##Checking condition FNR==NR which will be TRUE when first time Input_file is being read.
  sum+=$NF                                          ##Taking sum of last field of all lines here and keep adding them to get cumulative sum of whole Input_file.
  next                                              ##next will skip all further statements from here.
}
FNR==1{                                             ##Checking condition if its first line for 2nd time reading of Input_file.
  count=sum/3                                       ##Creating count with value of sum/3 here.
}
{
  curr_sum+=$NF                                     ##Keep adding lst field sum in curr_sum here.
}
(curr_sum>=count || FNR==1) && fileCnt<=2{          ##Checking if current sum is <= count OR its first line(in 2nd time reading) AND output file count is <=2 here.
  close(out_file)                                   ##Closing output file here, may NOT be needed here since we are having only 3 files here in output.
  out_file="file" ++fileCnt                         ##Creating output file name here.
  curr_sum=$NF                                      ##Keep adding lst field sum in curr_sum here.
}
{
  print > (out_file)                                ##Printing current line into output file here.
}'   Input_file  Input_file                         ##Mentioning Input_file names here.

回答2:

awk '{ L[nr++]=$0; sum+=$3 }
     END{ sumpf=sum/3; sum=0; file=1; 
          for(i in L) { split(L[i],a); 
          if ((sum+a[3])>sumpf && file<3) { file+=1; sum=0; }; 
          print i, L[i] > "file" file;
          sum+=a[3]; 
        }
    }'  input

• This script will read all input into array L, and calculate sum
• Int the END block the sumPerFile is calculated sumpf, and the output is done.

In contrast to the other solution, this only needs one inputfile.

来源：https://stackoverflow.com/questions/62425230/sum-value-of-a-3rd-row-and-divide-rows-accordingly