How to find button with Selenium by its text inside (Python)?

问题

I have the following three buttons that I can't figure out how to grab the text that is inside of them (e.g Outliers). I tried browser.find_element_by_link_text("Outliers").click(), but got "Unable to locate element" error. How can I do it?

回答1:

Another example XPath:

browser.find_element_by_xpath('//button[text()="Outliers"]')

回答2:

Try this XPath:

"//button[@class='three-state-item btn btn-default'][.='Outliers']".

回答3:

There are two ways :

1. By using text() method -
   browser.find_element_by_xpath('//button[text()="Outliers"]')
2. By using normalize-space() method - browser.find_element_by_xpath('//button[normalize-space()="Outliers"]')

Note : It is always better to use normalize-space() method as it will work even if there are spaces present at the start of your text or at the end of text, because normalize-space() method trim the left and right side spaces

来源：https://stackoverflow.com/questions/49906237/how-to-find-button-with-selenium-by-its-text-inside-python