Mysql: Select rows from a table that are not in another

问题

How to select all rows in one table that do not appear on another?

Table1:

+-----------+----------+------------+
| FirstName | LastName | BirthDate  |
+-----------+----------+------------+
| Tia       | Carrera  | 1975-09-18 |
| Nikki     | Taylor   | 1972-03-04 |
| Yamila    | Diaz     | 1972-03-04 |
+-----------+----------+------------+

Table2:

+-----------+----------+------------+
| FirstName | LastName | BirthDate  |
+-----------+----------+------------+
| Tia       | Carrera  | 1975-09-18 |
| Nikki     | Taylor   | 1972-03-04 |
+-----------+----------+------------+

Example output for rows in Table1 that are not in Table2:

+-----------+----------+------------+
| FirstName | LastName | BirthDate  |
+-----------+----------+------------+
| Yamila    | Diaz     | 1972-03-04 |
+-----------+----------+------------+

Maybe something like this should work:

SELECT * FROM Table1 WHERE * NOT IN (SELECT * FROM Table2)

回答1:

If you have 300 columns as you mentioned in another comment, and you want to compare on all columns (assuming the columns are all the same name), you can use a NATURAL LEFT JOIN to implicitly join on all matching column names between the two tables so that you don't have to tediously type out all join conditions manually:

SELECT            a.*
FROM              tbl_1 a
NATURAL LEFT JOIN tbl_2 b
WHERE             b.FirstName IS NULL

回答2:

You need to do the subselect based on a column name, not *.

For example, if you had an id field common to both tables, you could do:

SELECT * FROM Table1 WHERE id NOT IN (SELECT id FROM Table2)

Refer to the MySQL subquery syntax for more examples.

回答3:

SELECT *
FROM Table1 AS a
WHERE NOT EXISTS (
  SELECT *
  FROM Table2 AS b 
  WHERE a.FirstName=b.FirstName AND a.LastName=b.Last_Name
)

EXISTS will help you...

回答4:

A standard LEFT JOIN could resolve the problem and, if the fields on join are indexed,
should also be faster

SELECT *
FROM Table1 as t1 LEFT JOIN Table2 as t2 
ON t1.FirstName = t2.FirstName AND t1.LastName=t2.LastName
WHERE t2.BirthDate Is Null

回答5:

Try:

SELECT * FROM table1
    LEFT OUTER JOIN table2
    ON table1.FirstName = table2.FirstName and table1.LastName=table2.LastName
    WHERE table2.BirthDate IS NULL

回答6:

Try this simple query. It works perfectly.

select * from Table1 where (FirstName,LastName,BirthDate) not in (select * from Table2);

回答7:

This worked for me in Oracle:

SELECT a.* 
    FROM tbl1 a 
MINUS 
SELECT b.* 
    FROM tbl2 b;

回答8:

SELECT a.* FROM 
FROM tbl_1 a
MINUS
SELECT b.* FROM 
FROM tbl_2 b

来源：https://stackoverflow.com/questions/11767565/mysql-select-rows-from-a-table-that-are-not-in-another