How do I generate a Cartesian product in Java?

☆樱花仙子☆ 提交于 2019-11-27 18:13:32

问题


I have a number of ArrayList with each ArrayList having objects and each one can have different length. I need to generate permutation like in the below example:

suppose i have 2 arraylist

arraylist A has object a, object b and object c
arraylist B has object d, object e

Then the output should be 6 new arraylist with this combinations:

combination 1 object a and object d,
combination 2 object a and object e,
combination 3 object b and object d,
combination 4 object b and object e,
combination 5 object c and object d,
combination 6 object c and object e,

Can anyone help me?


回答1:


Guava 19+

Lists.cartesianProduct(List...)

E.g.:

List<Object> list1 = Arrays.asList("a", "b", "c");
List<Object> list2 = Arrays.asList("d", "e");
System.out.println(Lists.cartesianProduct(list1, list2));

Output:

[[a, d], [a, e], [b, d], [b, e], [c, d], [c, e]]



回答2:


With Java8 streams

    List<String> a = Arrays.asList("a", "b", "c");
    List<String> b = Arrays.asList("d", "e");
    String[][] AB = a.stream().flatMap(ai -> b.stream().map(bi -> new String[] { ai, bi })).toArray(String[][]::new);
    System.out.println(Arrays.deepToString(AB));

output

    [[a, d], [a, e], [b, d], [b, e], [c, d], [c, e]]

To get as List

    List<List<String>> ll = a.stream().flatMap(ai -> b.stream().map(bi -> new ArrayList<>(Arrays.asList(ai, bi)))).collect(Collectors.toList());



回答3:


With an Iterable+Iterator:

import java.util.*;

class CartesianIterator <T> implements Iterator <List <T>> {

    private final List <List <T>> lilio;    
    private int current = 0;
    private final long last;

    public CartesianIterator (final List <List <T>> llo) {
        lilio = llo;
        long product = 1L;
        for (List <T> lio: lilio)
            product *= lio.size ();
        last = product;
    } 

    public boolean hasNext () {
        return current != last;
    }

    public List <T> next () {
        ++current;
        return get (current - 1, lilio);
    }

    public void remove () {
        ++current;
    }

    private List<T> get (final int n, final List <List <T>> lili) {
        switch (lili.size ())
        {
            case 0: return new ArrayList <T> (); // no break past return;
            default: {
                List <T> inner = lili.get (0);
                List <T> lo = new ArrayList <T> ();
                lo.add (inner.get (n % inner.size ()));
                lo.addAll (get (n / inner.size (), lili.subList (1, lili.size ())));
                return lo;
            }
        }
    }
}

class CartesianIterable <T> implements Iterable <List <T>> {

    private List <List <T>> lilio;  

    public CartesianIterable (List <List <T>> llo) {
        lilio = llo;
    }

    public Iterator <List <T>> iterator () {
        return new CartesianIterator <T> (lilio);
    }
}

You can use them in a simplified for-loop:

class CartesianIteratorTest {

    public static void main (String[] args) {
        List <Character> la = Arrays.asList (new Character [] {'a', 'b', 'c'});
        List <Character> lb = Arrays.asList (new Character [] {'d', 'e'});      
        List <List <Character>> llc = new ArrayList <List <Character>> ();
        llc.add (la);
        llc.add (lb);

        CartesianIterable <Character> ci = new CartesianIterable <Character> (llc);
        for (List<Character> lo: ci)
            show (lo);
    }

    public static void show (List <Character> lo) {
        System.out.print ("(");
        for (Object o: lo)
            System.out.print (o);
        System.out.println (")");
    }
}



回答4:


Use nested for loops that would have a loop for every ArrayList as below. I am assuming I have two ArrayLists - intList and stringList. I can have two nested for loops (one for each list) to generate the permutation.

    for(Integer i : intList){
        for (String s : stringList) {
            ...
        }
    }



回答5:


Use Guava...here is an example of a Cartesian product of a list with itself:

public static void main(String[] args){
    //How to do a cartesian product of a List of items
    List<Integer> listToSelfMultiply = Arrays.asList(new Integer(1), new Integer(2), new Integer(3), new Integer(4));
    LinkedList<Integer> linkedListCopy = Lists.newLinkedList(listToSelfMultiply);
    for (Integer i:listToSelfMultiply) {
        if(linkedListCopy.size() == 1) {
            break;
        }
        linkedListCopy.remove();
        System.out.println("" + Arrays.deepToString(Lists.cartesianProduct(Arrays.asList(i), linkedListCopy).toArray()) + "");
    }
}


来源:https://stackoverflow.com/questions/8082595/how-do-i-generate-a-cartesian-product-in-java

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!