问题
I have a service which has two operations.
RegisterUser
UpdateUser
I have a camel rout:
<camel:route id="myRoute">
<camel:from uri="cxf:bean:myListenerEndpoint?dataFormat=POJO&synchronous=true" />
<camel:bean ref="processor" method="processMessage"/>
<camel:to uri="xslt:file:resources/service/2.0.0/UserRegistration.xsl"/>
<camel:to uri="cxf:bean:myTargetEndpoint"/>
</camel:route>
In my processor bean, when I specify:
RegisterUser registerUser = exchange.getIn().getBody(RegisterUser.class);
I get the register user object. Everything works fine. The problem is that I want camel to route my request conditionally, for e.g:
If the service operation is RegisterUser
I want to route the message to my specific bean and if the service operation is UpdateUser
I want to route the message to the other bean.
I have tried to use camel xPath, but it not seems to be working.
<camel:route id="myRoute">
<camel:from uri="cxf:bean:myListenerEndpoint?dataFormat=POJO&synchronous=true" />
<camel:choice>
<camel:when>
<camel:xpath>
//RegisterUser
</camel:xpath>
<camel:bean ref="processor" method="processMessage"/>
<camel:to uri="xslt:file:resources/service/2.0.0/UserRegistration.xsl"/>
</camel:when>
</camel:choice>
<camel:to uri="cxf:bean:myTargetEndpoint"/>
</camel:route>
I was searching how to set up camel to route to the different targets but did not find anything. Maybe somebody knows where might be the problem?
回答1:
The information of the operation required will be in the header of the message.
The header you are looking for is called 'operationName'
So here is an example :
<camelContext xmlns="http://camel.apache.org/schema/blueprint">
<route id="example">
<from uri="cxf:bean:myListenerEndpoint?dataFormat=POJO&synchronous=true" />
<log message="The expected operation is :: ${headers.operationName}" />
<choice>
<when>
<simple>${headers.operationName} == 'RegisterUser'</simple>
<bean ref="processor" method="processMessage"/>
<to uri="xslt:file:resources/service/2.0.0/UserRegistration.xsl"/>
</when>
<when>
<simple>${headers.operationName} == 'UpdateUser'</simple>
<!-- Do the update user logic here -->
<bean ref="processor" method="updateUser" />
</when>
</choice>
<to uri="cxf:bean:myTargetEndpoint"/>
</route>
</camelContext>
(Note the example is using apache aries blueprint - but it will be identical for spring, other than the namespace)
回答2:
try using camel-simple expressions instead of xpath for this...
<when><simple>${body} is 'com.RegisterUser'</simple><to uri="..."/></when>
回答3:
Spring XML route In my case I use inbound Jetty EP. I check parametr in request. Invole URL http://localhost:8080/srv?alg=1
<choice id="_choice1">
<when id="_when1">
<simple>${in.header.alg} == '1'</simple>
<log id="_log10" message="LOG ALG 1"/>
</when>
...
<otherwise id="_otherwise1">
<setFaultBody id="_setFaultBody1">
<constant>Return message about ERROR</constant>
</setFaultBody>
</otherwise>
</choice>
回答4:
final CamelContext context = exchange.getContext();
if (isAlive) {
context.startRoute("table-reader-route");
log.info("starting dailycase route= " + response);
} else {
context.stopRoute("table-reader-route");
log.info("stoping dailycase route= " + response);
}
来源:https://stackoverflow.com/questions/11691074/apache-camel-conditional-routing